In a particular steam engine, the boiler temperature is 128 C and the chilly reservoir temperature is 29 C.?
Query by Evan: In a particular steam motor, the boiler temperature is 128 C and the cold reservoir temperature is 29 C.?
Although this engine does three kcal of operate, what minimum volume of heat should be discharged into the cold reservoir?
Reply by Ivan A
Assuming it is a carnot motor, the efficiency is given by
performance = 1 – Tc/Th = one – (29+273) / (128+273) = 24 %
As a result, the minimum warmth input is
Qh > 3 / .24 = twelve.five
Qc > 12.five – three = 9.5
Qcmin = nine.5 kcal
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